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x^2+13x-86=0
a = 1; b = 13; c = -86;
Δ = b2-4ac
Δ = 132-4·1·(-86)
Δ = 513
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{513}=\sqrt{9*57}=\sqrt{9}*\sqrt{57}=3\sqrt{57}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-3\sqrt{57}}{2*1}=\frac{-13-3\sqrt{57}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+3\sqrt{57}}{2*1}=\frac{-13+3\sqrt{57}}{2} $
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